Kepler's Third Law of Motion
Also called the 'Law of Periods'
Kepler’s Third Law helps us understand the relationship between how long a planet takes to complete one orbit around the Sun and the size of its orbit.
The relationship is expressed as:
\[\frac{T^2}{a^3} = \text{constant}\]
Where:
For planets orbiting the Sun, this constant is approximately the same for all planets.
Let’s compare Jupiter and Saturn, two gas giants in our solar system, using Kepler’s Third Law.
Jupiter:
Distance from the Sun: 5.2 AU
Orbital period: ~ 11.86 Earth years
Saturn
Distance from the Sun: 9.58 AU
Orbital period: about 29.46 Earth years
Using Kepler’s Third Law, we calculate the constant for both planets:
For Jupiter: \[
k_{Jupiter} = \frac{T_{Jupiter}^2}{a_{Jupiter}^3} = \frac{11.86^2}{5.2^3} \approx 1.00037
\]
For Saturn:
\[
k_{Saturn} = \frac{T_{Saturn}^2}{a_{Saturn}^3} = \frac{29.46^2}{9.58^3} \approx 0.98712
\]
Since Saturn is almost twice as far from the Sun as Jupiter, it takes significantly longer to complete one orbit. While Jupiter takes about 12 Earth years to orbit the Sun, Saturn, being farther away, takes nearly 30 Earth years.
The increase in orbital period is much greater than the increase in distance, which is why Kepler’s Third Law shows a relationship that scales with the cube of the distance and the square of the period.
These results also confirm that the constant \(k\) is approximately the same for both planets, verifying Kepler’s Third Law. The small difference arises due to rounding and slight variations in measurements.
The value of \(k\) for our solar system is approximately 1 when using years for the orbital period and astronomical units (AU) for the semi-major axis
\(a\).
“The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.”
Take a look at our posters, stickers, and more on the Socratica shop.
Kepler's First Law of Motion
Kepler's Second Law of Motion